Can someone explain the Option Chain of AMD for me?

Question

http://www.google.com/finance/option_chain?q=NYSE:AMD

Specifically, the $10 strike. What does the $1.99 put mean?

Answer 1

When you buy a put option, you're buying the right to sell stock at the "strike" price. To understand why you have to pay separately for that, consider the other side of the transaction. If I agree to trade stock for money at above market rates, I need to make up the difference somewhere or face bankruptcy.

That risk of loss is what the option price is about. You might assume that means the market expects the price of AMD to fall to 8.01 from it's current price of 8.06 by the option expiration date. But that would also mean call options below the market price is worthless. But that's not quite true; people who price options need to factor in volatility, since things change with time. The price MIGHT fall, and traders need to account for that risk. So 1.99 roughly represents the probability of AMD rising to 10. There's probably some technical analysis one can do to the chain, but I don't see any abnormality of AMD here.

Answer 2

The buyer pays $1.99/share for the option of selling a share of AMD to the seller for $10 which is currently $1.94 higher than the price of $8.06/share. If you bought the put and immediately exercised it, you would come out of the deal losing $.05/share.

Answer 3

The current price is $8.05. If you want the right to sell it to someone (put it to the buyer) for $10, you have to pay $2. Since you're looking at an expiration that's so close, the "in the money" value is nearly the same as what it trades for. The JAN 2013 sells for nearly $3.