Preamble
The demonstration in the link states "The growth rate in this example would be the 5% increase per year", so although you mention substituting the growth rate of 3% I assume you mean that the 5% growth rate should be substituted by a fixed $25 increase. You can swap the figures as you please in the formula. The point is I'm fairly sure you want the growth rate substituted, not the interest rate. (In the example in the link 3% is the interest rate.)
Solution
I doubt you'll find a formula quoted so here is one derived, based on the example.
The formula on the link, with the example shown, can be found like this.
First, adding up the contribution from each year:-
2000*(1 + 0.05)^0*(1 + 0.03)^4 +
2000*(1 + 0.05)^1*(1 + 0.03)^3 +
2000*(1 + 0.05)^2*(1 + 0.03)^2 +
2000*(1 + 0.05)^3*(1 + 0.03)^1 +
2000*(1 + 0.05)^4*(1 + 0.03)^0 = 11700.75
This can be expressed as a sum like so:-

or simplified (using Mathematica ) to produce the formula:-

The calculation you require, with fixed $25 growth, is this:-
(2000 + 25*0)*(1 + 0.03)^4 +
(2000 + 25*1)*(1 + 0.03)^3 +
(2000 + 25*2)*(1 + 0.03)^2 +
(2000 + 25*3)*(1 + 0.03)^1 +
(2000 + 25*4)*(1 + 0.03)^0 = 10875.88
which can be expressed in this sum:-

This can be simplified in a couple of ways:-

So, taking the shorter version
FV = -((x - (1 + i)^n (i p + x) + i (p + n x))/i^2)
e.g.
x = 25
p = 2000
i = 0.03
n = 5
FV = 10875.88